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by ketkoag » Sat Jun 20, 2009 1:35 am
There are 6 boxes numbered 1, 2,....6. Each box is to be filled up either with a red or a green ball in such a way that at least 1 box contains a green ball and the boxes containing green balls are consecutively numbered. The total number of ways in which this can be done is

A. 5
B. 21
C. 33
D. 60
E. 6
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Source: — Problem Solving |

by rahulg83 » Sat Jun 20, 2009 2:39 am
21


six boxes, all green no of cases = 1 GGGGGG
five green, one red = 2 GGGGGR, RGGGGG
four green, two red = 3 GGGGRR, RRGGGG, RGGGGR
three green three red = 4 u can figure out rest of'em in similar manner
two green, four red = 5
one green, five red = 6

Add all cases, come up to 21.

OA?
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by ketkoag » Mon Jun 22, 2009 4:17 am
21 it is.. thanks..
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