BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

42 fruits in all

Expert replies
by sanju09 » Wed Jan 13, 2010 4:40 am
Edburg bought some apples, mangoes, and bananas. He bought 42 fruits in all. The number of bananas he bought is less than half the number of apples he bought; the number of mangoes he bought is more than one-third the number of apples he bought but less than three-fourths the number of bananas he bought. How many bananas did he buy?
(A) 5
(B) 6
(C) 8
(D) 11
(E) 12
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
Join the discussion
Source: — Problem Solving |

by Yes.WeCan » Wed Jan 13, 2010 7:40 am
Is it D?
Join the discussion

by ace_gre » Wed Jan 13, 2010 5:51 pm
Hi, here is my approach

A + M + B= 42----(1)
Also M < A/2 -----(2)
M> A/3-------------(3)
M< (3/4) B--------(4)

Based on the last equation , M < 3/4 B, I took B has to be a multiple of 4. Of the choices provided only C and E are possible.

Testing with B =8, M < 6. So it can be 1,2,3..5.
if M=1, A = 42 - (1+8)= 33. Not valid since eq 3 is not satisfied.
if M=5, A = 42 -( 5+8) =29. Eq 3 not satisfied.

So testing with B=12, M <9. M can be 1,2,...8
if M=1, B=12, A= 42 - (1+12) =29. Eq 3 not satisfied
if M=8, B=12, A= 42 - (8+12) = 22. All equations are satisfied.

Actually if we do not assume the whole number of bananas to start with 11 also works.
Both 11 and 12 works :?:
Join the discussion

by Testluv » Wed Jan 13, 2010 8:35 pm
sanju09 wrote:Edburg bought some apples, mangoes, and bananas. He bought 42 fruits in all. The number of bananas he bought is less than half the number of apples he bought; the number of mangoes he bought is more than one-third the number of apples he bought but less than three-fourths the number of bananas he bought. How many bananas did he buy?
(A) 5
(B) 6
(C) 8
(D) 11
(E) 12
A + M + B = 42

Because we are dealing with objects, all values must be positive integers.

Translating the second sentence into a series of inequalities, we have:

B < A/2, which, because we are dealing only with positive integers, can be safely rewritten as: A > 2B;

M > A/3, which can be rewritten as: 3M > A; and

M < 3B/4

Thus:

3M > A > 2B

we can see that 3M > 2B or M > 2B/3...and we also know that M < 3B/4
(ie, 2B/3 < M < 3B/4)

Now, we have to test the answer choices against the last two inequalities that I wrote (ie, the ones I've emboldened). When backsolving, in general, we should start from B or D. (although for this particular question, it wouldn't really matter).

Looking at B: if the number of Bananas is 6, then M > (2*6)/3 and M < (3*6)/4,
or 4 < M < 4.5, which makes the number of mangoes a non-integer, and therefore this choice is incorrect.

Looking at D: If B = 11, then M > (2*11)/3 and M < (3*11)/4 or 7.3333 < M < 8.25. Then, the number of mangoes is 8. If there are 8 mangoes, 11 bananas, and 42 fruit in total, then there are 23 apples. These numbers satisfy all of the inequalities. As there can only be one answer choice that satisfies all the conditions (ie, the correct answer), the correct answer is choice D.
Last edited by Testluv on Thu Jan 14, 2010 12:17 am, edited 1 time in total.
Kaplan Teacher in Toronto
Join the discussion

by Testluv » Wed Jan 13, 2010 9:45 pm
Based on the last equation , M < 3/4 B, I took B has to be a multiple of 4. Of the choices provided only C and E are possible.


But it's not an equation. It's an inequality. And you can't apply this thinking when dealing with an inequality. That is, the number of mangoes can be less than three-fourths the number of bananas without the number of bananas being a multiple of 4. For example, if we had 10 bananas, and 2 mangoes, then, because three-fourths of 10 is 7.5, the inequality is satisfied even though the number of bananas (ie, 10) is not a multiple of 4.
Kaplan Teacher in Toronto
Join the discussion