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product of 7 consecutive integers

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Source: — Data Sufficiency |
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by gauravgundal » Thu Aug 13, 2009 2:31 am
IMO -D
Please let me know if i am correct. i will explain you if my answer is correct
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Re: product of 7 consecutive integers

by tohellandback » Thu Aug 13, 2009 2:38 am
apoorva.srivastva wrote:If the product of 7 consecutive integers is not zero, is the product negative?

1.) The largest number is less than 7
2.) At least on of the numbers is negative
IMO D because:
product is non zero, so 0 is not one of the numbers.
tha means numbers are all negative or all positive.

1) largest number less than 7
the largest number cannot be positive because in that case 0 will be one of the numbers.
so all numbers are negative. product is negative.
SUFFICIENT

2) the numbers can either be all negative or all positive
one number is negative means all numbers are negative

SUFF
The powers of two are bloody impolite!!
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by apoorva.srivastva » Thu Aug 13, 2009 9:53 am
OA is D
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by vikram_k51 » Thu Aug 13, 2009 9:54 am
If the product of 7 consecutive integers is not zero, is the product negative?

1.) The largest number is less than 7
2.) At least on of the numbers is negative

A alone is sufficient.As From the question stem and A it is clear that the 7 numbers here are all negative and hence their product is negative.
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by dikku07 » Thu Aug 13, 2009 1:23 pm
IMO D
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by jjk » Mon Aug 17, 2009 6:52 pm
vikram_k51 wrote:If the product of 7 consecutive integers is not zero, is the product negative?

1.) The largest number is less than 7
2.) At least on of the numbers is negative

A alone is sufficient.As From the question stem and A it is clear that the 7 numbers here are all negative and hence their product is negative.
BOTH are sufficient. Statement 2 is sufficient b/c if the integers are consecutive, and only one is negative, the other numbers could cross 0 and enter "positive territory." This would render the product of the numbers in the set equal to 0, which violates the condition stated in the original passage. Therefore, according to Statement 2, all the numbers must be negative.
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