Q: If i and j are integers, is i+j an even integer?
(1) i<10
(2) i=j
The answer given is B.
The explanation: If i=j, then i+j can also be expressed as i+j when i is substituted for j in the expression. This can be simplified as 2i, and since 2 times any integer (HERE IS WHERE I FEEL THE ASSUMPTION IS WRONG) produces and even integer, then i+j must be an even integer; SUFFICIENT.
My doubt is: There is a case where, if i=j=0; 0 is neither an even integer, nor an odd integer. Therefore 2i may not be even when i=0. Thus shouldn't the answer be E.
Any help will be appreciated.
(1) i<10
(2) i=j
The answer given is B.
The explanation: If i=j, then i+j can also be expressed as i+j when i is substituted for j in the expression. This can be simplified as 2i, and since 2 times any integer (HERE IS WHERE I FEEL THE ASSUMPTION IS WRONG) produces and even integer, then i+j must be an even integer; SUFFICIENT.
My doubt is: There is a case where, if i=j=0; 0 is neither an even integer, nor an odd integer. Therefore 2i may not be even when i=0. Thus shouldn't the answer be E.
Any help will be appreciated.
