ANS 15
Here its goes
2^[x-2] can be written as [2^x]/[2^2].
Now, solve the eq given in question
LHS = [2^x]-[[2^x]/[2^2]] = [2^x][1-1/4] = 3*[2^x]/4 = 3*[2^x-2]
RHS = 3*2^13
Equate LHS and RHS
x-2=13
so, x = 15
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Source: Beat The GMAT — Problem Solving |
Thanks.
Another way that I have figured out with the help of this forum:
Factor out 2^x-2
You get 2^x-2( 2^2 - 1) = 3(2^13)
2^x-2( 3) = 3(2^13)
x = 15
Another way that I have figured out with the help of this forum:
Factor out 2^x-2
You get 2^x-2( 2^2 - 1) = 3(2^13)
2^x-2( 3) = 3(2^13)
x = 15
