'manpreet singh wrote:Q.1 At a certain pizzeria, 1/6 of the pizzas sold in a week were cheese, and 1/5 of the
OTHERpizzas sold were pepperoni. If Brandon bought a randomly chosen pizza from
the pizzeria that week, what is the probability that he ordered a pepperoni?
Let the total = 30.
Cheese = (1/6)30 = 5.
Other pizzas = 30-5 = 25.
Pepperoni = (1/5)25 = 5.
P(pepperoni) = pepperoni/total = 5/30 = 1/6.
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