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Area of Triangle ABD

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Senior | Next Rank: 100 Posts
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by sairamGmat » Wed Aug 11, 2010 12:43 am
In the figure above, CE = 5, BD = 8, and the area of quadrilateral ABCD is 36. What is the area of â–³ABD ?
(A) 4
(B) 9
(C) 16
(D) 20
(E) 56

OA is C . Can any one tell me how this arrived?
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by gmatmachoman » Wed Aug 11, 2010 12:48 am
Area of (ABD) = Area of ABCD - Area of BCD


So Area of BCD = 1/2 * BD * CE
= 1/2 *8 *5
=20

Area of (ABD) = 36 -20
= 16
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by likithae » Wed Aug 11, 2010 1:22 am
gmatmachoman wrote:Area of (ABD) = Area of ABCD - Area of BCD


So Area of BCD = 1/2 * BD * CE
= 1/2 *8 *5
=20

Area of (ABD) = 36 -20
= 16

thank you very much..... i understood how to solve this problem.....
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