x2 = 2 (x1) - 1. x1 = 3 so x2 = (2*3) - 1 = 5.JGS wrote:How do you determine
x2=5 and x3=9?
Similar logic for x3 and so on
- pradeep
Similar logic for x3 and so on
- pradeep
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Sequence problem
Similar logic for x3 and so on
- pradeep
x1 = 3 and xn+1 = 2xn – 1 for n 1
How did you go from
xn+1 = 2xn – 1
to
x2= 2(x1)-1
x3= 2(x2)-1
where did the "+1" go for "xn+1"?
Thanks
How did you go from
xn+1 = 2xn – 1
to
x2= 2(x1)-1
x3= 2(x2)-1
where did the "+1" go for "xn+1"?
Thanks
