x2 = 2 (x1) - 1. x1 = 3 so x2 = (2*3) - 1 = 5.JGS wrote:How do you determine
x2=5 and x3=9?
Similar logic for x3 and so on
- pradeep
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x2 = 2 (x1) - 1. x1 = 3 so x2 = (2*3) - 1 = 5.JGS wrote:How do you determine
x2=5 and x3=9?
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