Problem Solving

JGS wrote:How do you determine

x2=5 and x3=9?

x2 = 2 (x1) - 1. x1 = 3 so x2 = (2*3) - 1 = 5.

Similar logic for x3 and so on

- pradeep

x1 = 3 and xn+1 = 2xn – 1 for n 1

How did you go from

xn+1 = 2xn – 1

to

x2= 2(x1)-1

x3= 2(x2)-1

where did the "+1" go for "xn+1"?

Thanks