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Exponents (dealing with fractions)

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by bstalling » Mon Feb 23, 2009 2:14 pm
D-35

(1/5)^m * (1/4)^18 = (1/2(10)^35)
5^(-1m) * 2^(-1*2*18) = 1/2(10^35)
5^(-1m) * 2^-36 = 1/2(10^35)
(2^-1)[5^(-1m) * 2^-35] = 1/2(10^35)
or
1/2(10^35)
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by relaxin99 » Mon Feb 23, 2009 2:20 pm
bstalling wrote:D-35

(1/5)^m * (1/4)^18 = (1/2(10)^35)
5^(-1m) * 2^(-1*2*18) = 1/2(10^35)
5^(-1m) * 2^-36 = 1/2(10^35)
(2^-1)[5^(-1m) * 2^-35] = 1/2(10^35)
or
1/2(10^35)

I dont understand how you got down to the last two lilnes, everything else i completed understand
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by bstalling » Mon Feb 23, 2009 2:30 pm
I think you are stuck at this point: (2^-1)[5^(-1m) * 2^-35] = 1/2(10^35)

Factor out a (2^-1) from 2^(-36) means you subtract 1 from 36 thus 2^(-35)

OR

10^35 = (2*5)^35 = (2^35)*(5^35), hence why we factored above
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