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Source: — Data Sufficiency |
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by maihuna » Tue Feb 15, 2011 10:28 am
From 1: m>3z, from 2 4z>m
=> 3z<m<4z

If z<0, then above condition is not possible as then : 4z<m<3z will be right inequality

=> z>0 and so is m and so m+z>0

ANother way : Add both eq: z>0, use any of them : m>3z>0

so each of m and z are positive
Charged up again to beat the beast :)
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