BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

any shortcuts for this question ?

Expert replies
by abhasjha » Tue Dec 03, 2013 8:37 am
If x, y, and z are integers and xy+z is an odd integer, is x an even integer?

1. xy+xz is an even integer

2. y+xz is an odd integer
Join the discussion
Source: — Data Sufficiency |

by Brent@GMATPrepNow » Tue Dec 03, 2013 8:54 am
abhasjha wrote:If x, y, and z are integers and xy + z is an odd integer, is x an even integer?

1. xy + xz is an even integer
2. y + xz is an odd integer
Target question: Is x an even integer?

Given: xy + z is an odd integer

Statement 1: xy + xz is an even integer
Notice that xy + xz and xy + z have an xy term in common.
Let's use the fact that EVEN - ODD = ODD
So, (xy + xz) - (xy + z) = ODD
Simplify: xz - z = ODD
Factor: z(x - 1) = ODD
IMPORTANT: If the product of two integer values is ODD, then BOTH values must be ODD.
So, z is ODD and (x - 1) is ODD.
If x - 1 is ODD, then x must be EVEN
Since we can answer the target question with certainty, statement 1 is SUFFICIENT

Statement 2: y + xz is an odd integer
Let's use the fact that ODD + ODD = EVEN
So, (y + xz) + (xy + z) = EVEN
Simplify: y + xz + xy + z = EVEN
Rearrange: xz + z + xy + y = EVEN
Factor in pieces: z(x + 1) + y(x + 1) = EVEN
Simplify: (z + y)(x + 1) = EVEN
At this point, we can see that (x + 1) can be either ODD or EVEN, which means x can be either ODD or EVEN
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT

Answer = A

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion