In how many different ways can a group of 8 people be divided into 4 teams of 2 people each?
90
105
168
420
2520
90
105
168
420
2520
I think similar questions have been posted before
Anyways I can use the practice.
There are 8 ppl. so there are 8! ways to arrange then.
However you want to choose four teams each with 2 ppl in them. Each team can be arranged 2! ways.
so the answer is 8!/(2!*2!*2!*2!) = 2520
You can do it an alternative way as well.
You have 8 ppl. You want to choose 2. So first team = 8C2,
out of 6 ppl remaining you want to choose 2 more... so 6C2,
and so on.. you get 4C2 and 2C2 for the remaining teams.
Multiply the lot you get 8C2*6C2*4C2*2C2
