Probability Q Set -7

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Probability Q Set -7

by [email protected] » Sun Sep 16, 2007 6:36 pm
Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl; then a second card is drawn. If the cards are drawn at random and if the sum of the numbers on the cards is 8, what is the probability that one of the two cards drawn is numbered 5 ?
A. 61 4
B. 51
C. 31
D. 52
E. 32
Source: — Problem Solving |

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by kajcha » Sun Sep 16, 2007 6:45 pm
Are you sure these are the options?

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by [email protected] » Sun Sep 16, 2007 8:09 pm
I am sorry.was typo
The options are
1. 1/6
2.1/5
3.1/3
4.2/5
5.2/3

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by raulverde » Sun Sep 16, 2007 8:09 pm
some thing is wrong about the choices. I get 1/3 as the answer

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by [email protected] » Sun Sep 16, 2007 8:13 pm
I have rectified the choices.
However your answer is incorrect.
I was able to solve now.
The answer will be 2/5.
total possible cases so that sum is 8 are: (2,6) (6,2) (3,5) (5,3) (4,4).
you have to choose only (3,5) and (5,3)
hence 2/5

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by raulverde » Sun Sep 16, 2007 8:17 pm
mah bad, i counted (4,4) twice