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- by determined
Sun Nov 01, 2009 11:48 pm- Forum: Problem Solving
- Topic: Probability of independent events
- Replies: 3
- Views: 1482
Probability of independent events
Probability that student A can solve the problem=1/3 Probability that student B can solve the problem=1/5 Probability that only one of them can solve the problem=? How would you solve this problem? I thought since they are independent events, p(AUB)= p(A)+P(B)-p(A and B)= 1/3+1/5-1/3.1/5= 7/15 but i...
- by determined
Sun Nov 01, 2009 7:42 pm- Forum: Problem Solving
- Topic: Probability of independent events
- Replies: 3
- Views: 1482