Search found 26 matches
- by francopiccolo
Fri May 29, 2009 12:23 am- Forum: Suggestions and Feedback
- Topic: Furthur Division of Quant Section
- Replies: 6
- Views: 3159
The customer spent:
0,7A + 0,5B = 6,3 -->
A = (6,3 - 0,5B)/0,7 = 9 - 5/7B
B must be a number such that 5/7B is an integer, then B can be 0, 7, 14, etc.
If B is 0, A is 9. But 9 is not a possible answer.
If B is 7, A is 4 and answer is 11.
- by francopiccolo
Mon May 25, 2009 4:09 pm- Forum: Problem Solving
- Topic: Apples and Bananas
- Replies: 1
- Views: 1030
The researcher concludes that a low inmmune system activity is the cause of mental illness, but it could be the other way round. Hence D.
- by francopiccolo
Mon May 25, 2009 2:19 pm- Forum: Critical Reasoning
- Topic: Immune- System Activity
- Replies: 9
- Views: 3130
- by francopiccolo
Thu May 21, 2009 7:02 pm- Forum: Reading Comprehension
- Topic: British business
- Replies: 10
- Views: 6875
I don't understand why 7 is E.
How much time should I spend in this task? I spent 16 minutes, I think that is a lot, hehe.
- by francopiccolo
Thu May 21, 2009 12:21 pm- Forum: Reading Comprehension
- Topic: Senior Managers
- Replies: 10
- Views: 4320
- by francopiccolo
Thu May 21, 2009 7:13 am- Forum: Data Sufficiency
- Topic: Parallel lines
- Replies: 12
- Views: 1836
- by francopiccolo
Wed May 20, 2009 8:50 pm- Forum: Data Sufficiency
- Topic: Parallel lines
- Replies: 12
- Views: 1836
Don't know if this is the faster approach, but here it goes. The prime factorization of 88000 is: 2^6 * 5 * 11. We have one Green chip, one red chip, and 2^6 can be divided into 8*8 or 4*4*4. As 8 is a number that satisfies the conditions for the value of the purple chip. We know that there are 2 pu...
- by francopiccolo
Wed May 20, 2009 7:44 pm- Forum: Problem Solving
- Topic: Number properties question
- Replies: 5
- Views: 1305
dtweah wrote:
Cool Scooby. Or for the formula wonks:
P=P(S|M)= P(S and M)/P(M) = 1/3/1/10 =10/3
Q=P(S|F)= P(S and F)/P(F) =2/3/9/10 = 20/27
P/Q= 10/3 x 27/20 =4.5
Actually, P(S and M) is 1/3 / P(S) and P(S and F) is 2/3 / P(S), but the P(S) is simplified in P/Q. I suppose you know that, but just in case.
- by francopiccolo
Wed May 20, 2009 7:33 pm- Forum: Problem Solving
- Topic: Probability
- Replies: 4
- Views: 1946
- by francopiccolo
Tue May 19, 2009 8:53 pm- Forum: Data Sufficiency
- Topic: Find the Numbers
- Replies: 5
- Views: 1573
For n = 100 we have that 75 numbers which differ in 25. From 26 to 100. If we add 101 we could substract the number 76, eliminating one pair of numbers that differ in 25 and not adding any pair of numbers. Then if we can substract one pair of number every time we add a number we need to add 25, ther...
- by francopiccolo
Tue May 19, 2009 8:33 pm- Forum: Data Sufficiency
- Topic: Sub-setting II
- Replies: 1
- Views: 974
- by francopiccolo
Tue May 19, 2009 6:10 pm- Forum: Problem Solving
- Topic: Probability Encore
- Replies: 5
- Views: 2003
This took me long, I hope someone knows a faster approach. We know that 3, 6 and 9 are multiples of 3. We know that the remainders of dividing these numbers by 3 are:: 1 = 2, 2 = 1, 4 = 1, 5 = 2, 7 = 1, 8 = 2. To have numbers which sum a multiple of 3, each number with remainder 1 must be accompanie...
- by francopiccolo
Tue May 19, 2009 5:16 pm- Forum: Data Sufficiency
- Topic: Sub-setting
- Replies: 1
- Views: 1345
P(W OR E) = P(W) + P(E) - P(W AND E)
From (i), P(W AND E) = 0 NOT SUFF.
From (ii), P(W) - P(E) = 0,2 NOT SUFF.
Together, NOT SUFF.
- by francopiccolo
Mon May 18, 2009 5:24 pm- Forum: Data Sufficiency
- Topic: Box of red, blue balls
- Replies: 1
- Views: 1017
n is a multiple of 5, thus p or q are equal to 5.
For x to be a multiple of 5, x must contain twice the factor 5.
In p^2q^2 we have twice p and twice q therefore we have twice the factor 5, we don't know if thanks to p or thanks to q, but that is the right answer.
- by francopiccolo
Mon May 18, 2009 5:09 pm- Forum: Problem Solving
- Topic: Number Properties Question
- Replies: 2
- Views: 1240