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Let x be the length of the isosceles sides, therefore the hypotenuse = x.sqrt(2) Since 2x + x.sqrt(2) = 16 + 16sqrt(2) If we compare the rational(2x) with the rational (16) and the irrational (x.sqrt(2)) with the irrational (16sqrt(2)), we cannot get a solution. Therefore we try to compare the ratio...
- by daimaomee
Sun Feb 22, 2009 7:52 pm- Forum: Problem Solving
- Topic: right anngle isosceles
- Replies: 5
- Views: 2867
Assume Tim's mother catches up with Tim after riding for t hours, at that time, Tim's mother is 36t miles from home and Tim is 9(t + 1/4) miles from home Therefore 36t = 9(t + 1/4) Solving for t, we get t = 1/12 and therefore distance that Tim's mother has driven by 36/12 = 3 miles Therefore, answer...
- by daimaomee
Sun Feb 22, 2009 5:37 am- Forum: Problem Solving
- Topic: Distance Time problem
- Replies: 6
- Views: 2280
Daimaomee, sqrt(25-1.4^2) = 4.8.......any easy way of calculating this precisely?? Hi GID09, I have an "ancient" way to find the square root of a number: (i) Separate the number in group of 2 digits (if it is a odd-digit number, leave the leftmost number as single-digit) (ii) Starting fro...
- by daimaomee
Fri Feb 06, 2009 8:50 am- Forum: Problem Solving
- Topic: Reshma Salma and Mandip on a circle
- Replies: 9
- Views: 6532
IMO, the answer is E Draw a perpendicular line CQ from the centre of the circle to the chord RM. Since angle CQM is a right angle, CQ bisects RM Also, since triangle RSM is an isosceles triangle, a line which bisects and is perpendicular to its base will also pass through the vertex at S, i.e SCQ is...
- by daimaomee
Sun Feb 01, 2009 7:50 am- Forum: Problem Solving
- Topic: Reshma Salma and Mandip on a circle
- Replies: 9
- Views: 6532