Search found 31 matches


Let's try an experiment... I will give point out the conclusion and the reasoning and then see if that helps point people to the correct answer! We have a strengthen question. It is a normal type of question with a conclusion in the stimulus. That conclusion is that "the colleges in Tycho have fail...

by chintudave

Thu Mar 24, 2011 9:28 pm
Forum: Critical Reasoning
Topic: tycho city
Replies: 10
Views: 4660

Two faster ways to answer this problem without the mumbo jumbo! Common Realization for both the methods 1. From the problem it is clear that Ally and Betty have the same speed. So in my mind, i would eliminate Betty from the equation. i.e. I would make the problem simpler by assuming that there are...

by chintudave

Sat Mar 06, 2010 11:19 pm
Forum: Problem Solving
Topic: Time consuming rate problem
Replies: 14
Views: 1701

IMO E

Fewer is Countable and Lower is not. Therefore choices are B or E.

The hyphen between the "movies" and "fewer" in B breaks the sentence in correctly to make "-eater of the movies-".

Hence E.

by chintudave

Tue Feb 16, 2010 9:23 pm
Forum: Sentence Correction
Topic: GMAT Prep
Replies: 10
Views: 1279

Stupid Question!

Shouldn't "comparisons between products can be made at several stores" be "comparisons among products can be made at several stores" ?


What is being compared in this statement ?

by chintudave

Tue Feb 16, 2010 9:04 pm
Forum: Sentence Correction
Topic: What's wrong with the verbal statement
Replies: 6
Views: 904

IMO D. What is the OA ?

by chintudave

Sat Feb 13, 2010 11:44 pm
Forum: Critical Reasoning
Topic: must be true
Replies: 11
Views: 2003

[quote="Ian Stewart"][quote="harsh.champ"]If the integers m and n are chosen at random from integers from integers 1 to 100 with replacement, then the probability that a no. of the form 7m + 7n is divisible by 5 equals? (1)1/2 (2)1/4 (3)1/8 (4)1/16 (5)None of these ____________________ Problem solvi...

by chintudave

Fri Feb 05, 2010 11:50 pm
Forum: Problem Solving
Topic: Probability+Power+Divisibility rules
Replies: 6
Views: 2591

I thought the question was self sufficient. Stuart, am i overseeing something ? Based on what i interpret.... 5 Boys have 6 empty spots around them.... _B_B_B_B_B_ Let the girls pick four of the empty sport.... i.e. 6P4 = 360 The 5 boys can be adjusted in 5! ways So total combinations = 5! * 360 = 1...

by chintudave

Fri Feb 05, 2010 11:07 pm
Forum: Problem Solving
Topic: Permutation/Combination questions...
Replies: 25
Views: 13778

1. IMO B
2. IMO C

What are the OAs ? Will explain if I am right.

by chintudave

Sun Jan 31, 2010 9:57 pm
Forum: Reading Comprehension
Topic: Arbitration-judicial and political
Replies: 3
Views: 2209

With all the ambiguities out of the way. This is my painful way. Experts please share some quicker way! Since no two girls can sit together there are 30 unique options as listed below. 1-3-5-7 1-3-5-8 1-3-5-9 1-3-5-10 1-3-6-8 1-3-6-9 1-3-6-10 1-3-7-9 1-3-7-10 1-3-8-10 1-4-6-8 1-4-6-9 1-4-6-10 1-4-7-...

by chintudave

Fri Jan 29, 2010 6:25 pm
Forum: Problem Solving
Topic: Seating - Probability Question
Replies: 13
Views: 13283

Answer is C. Explanation: a. The given matrix is 9 dots on x axis and 6 dots on y axis. b. Choose 1 dot on y axis to plot the base of the triangle. 6C1 i.e 6 c. Choose 2 dots on x axis to plot the base on the y axis chosen in step b above. 9C2 i.e. 36 d. Now select 1 dot on y axis to plot the third ...

by chintudave

Tue Jan 26, 2010 11:53 pm
Forum: Problem Solving
Topic: coordinate geometry + combination
Replies: 5
Views: 1517

[quote="armaan700+"]The median value of a set of 9 positive integers is 6. If the only mode in the distrubution is 25 what is the least possible mean of the distribution.[/quote] Based on the data the set could be a. 1,2,3,4,6,7,8,9,25 b. 1,3,4,5,6,11,15,18,25 c. 1,2,4,5,6,25,25,25,25 . . . . . Are ...

by chintudave

Tue Jan 26, 2010 8:55 pm
Forum: Problem Solving
Topic: mean
Replies: 3
Views: 946
by chintudave

Tue Feb 24, 2009 9:09 pm
Forum: Problem Solving
Topic: 200 and 300 (both inclusive)
Replies: 16
Views: 22959

Re: 200 and 300 (both inclusive)

[quote="marcusking"]divisble by 2 = 1+100/2 =51 divisble by 3 =1+99/3 = 34 divisble by 5 = 1+100/5 = 21 divisble by 6 (both 2 and 3)= 1+94/6 =16 divisble by 15 (both 3 and 5)= 1+90/15 =7 divisble by 10 (both 2 and 5)= 1+100/10 =11 divisble by 30 (both 2,3 and 5)= 1+90/30 =4 Nos. divisble by 2/3/5 = ...

by chintudave

Tue Feb 24, 2009 7:36 pm
Forum: Problem Solving
Topic: 200 and 300 (both inclusive)
Replies: 16
Views: 22959

m + n = (z+4) + (y+e) = (z+e) + (y+4) = 10 + (-5) = 5

Hence C

by chintudave

Sun Feb 22, 2009 2:15 pm
Forum: Problem Solving
Topic: Addition Question
Replies: 6
Views: 1123

IMO A

My Bad!

Each option was a duplicate.

by chintudave

Fri Feb 20, 2009 10:44 pm
Forum: Problem Solving
Topic: permute with perfection
Replies: 13
Views: 2430