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So isnt (2^n)m(5^n) same as (10^n)m.

Since n is a positive integer so n>=1, m is always multiplied by 10 and m is also an integer. So units digit is always 0. We dont really need m or n for the answer.

where am I going astray here in this thinking

by gmathundred

Sun Oct 02, 2016 6:14 pm
Forum: Data Sufficiency
Topic: If m is 2-digit positive integer and n is a positive integer
Replies: 5
Views: 2837