Doubts in Circular permutation.

Hi all. So here is the first question I saw. 1. In how many ways can 5 gents and 5 ladies may sit together in a round table so that there are no two ladies together? Ans: 5 gents may be arranged by (n-1)! = (5-1)! = 4! 5 ladies occupy remaining positions in 5! way. Therefore we get 4!*5! = 2880 Here...