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subtracted 5*5*5 cases ( in which 4 is coming on 1st and 2nd place) from total number of cases.
We need to subtract because 4 is not allowed more than once and as 4 is an even integer and even integer is allowed only at first 2 places, so 4 can repeat only at first 2 places.
- by smarty80in
Wed Jul 02, 2008 9:08 am- Forum: Problem Solving
- Topic: How many five-digit numbers?
- Replies: 13
- Views: 10825
yes, but still 0 is an even integer See the page number 108 of OG11 it has given definition and list of even integer and the OG11 list includes clearly includes 0 Any integer that is divisible by 2 is an even integer, the set of even integers is {...,-4,-2,0,2,4,6,8,...} My sincere advice to all you...
- by smarty80in
Wed Jul 02, 2008 8:40 am- Forum: Problem Solving
- Topic: How many five-digit numbers?
- Replies: 13
- Views: 10825
yes 0 is an even integer
You can search "Is 0 an even integer" on google and you will get the answer
- by smarty80in
Mon Jun 30, 2008 9:16 am- Forum: Problem Solving
- Topic: How many five-digit numbers?
- Replies: 13
- Views: 10825
Correct Answer is C
The best answer is C. Not considering the fact that 4 cannot appear more than once, we have a total of 4*5*5*5*5=2500. Now we deduct the possibilities where 4 does appear more than once (in this case it can appear only twice on the two leftmost even digits). In order to do so, we put 4 in the first...
- by smarty80in
Mon Jun 30, 2008 7:48 am- Forum: Problem Solving
- Topic: How many five-digit numbers?
- Replies: 13
- Views: 10825