Search found 29 matches
@Krusto, you almost got it right: Equation 1 x/(x+y) = n x = nx+ny (n-1)x + ny = 0 y/x = (1-n)/n Equation 2 x/(x-y) = m x = mx - my (m-1)x - my = 0 y/x =(m-1)/m y/x+y/x = [(1-n)/n + (m-1)/m] = [(1-n)m + (m-1)n]/[nm] = (m-mn+mn-n)/mn= (m-n)/mn hence, (y/x)*2=(m-n)/mn; (y/x)=(m-n)/2mn; x/y=2mn/(m-n) w...
- by beatthegmat.garry
Mon Mar 05, 2012 4:29 am- Forum: Problem Solving
- Topic: Algebra
- Replies: 10
- Views: 1811
Hi Folks,
Are we talking about GMAT or any standardized test in general? Can GRE be used as a surrogate?
Thanks,
Garry
- by beatthegmat.garry
Thu Mar 01, 2012 6:28 pm- Forum: Research MBA Programs
- Topic: Retake the GMAT for Management Consulting: Cornell Admit
- Replies: 26
- Views: 27734
- by beatthegmat.garry
Wed Sep 21, 2011 7:09 pm- Forum: Problem Solving
- Topic: A jewelry store sells customized rings
- Replies: 10
- Views: 4637
Assuming angle x is angle(BCD)......
Since AD || BC, angle(BCD) and angle z are supplementary (they add upto 180 degrees).
So the question is reduced to finding what the value of angle z.
statement 1: no info about angle z
statement 2: z=40.
Hence B.
Thanks !
- by beatthegmat.garry
Sun Aug 21, 2011 7:02 pm- Forum: Data Sufficiency
- Topic: a data from gmat club
- Replies: 2
- Views: 894
Let n1, n2 and n3 be the 3 numbers: statement 1: Mean=3 and Median=3 therefore, (n1+n2+3)/3=3 .......n3=3. n1+n2=6. the possible combinations of n1 and n2 are (0,6)(1,5)(2,4)(3,3) Statement 2: Mode=3. Hence more than one number will be 3. Since n3 is assumed to be 3 we have either n1=n2=3. Hence C. ...
- by beatthegmat.garry
Sun Aug 21, 2011 6:50 pm- Forum: Data Sufficiency
- Topic: Mean and Mode
- Replies: 5
- Views: 1501
- by beatthegmat.garry
Mon Aug 15, 2011 10:10 pm- Forum: Data Sufficiency
- Topic: Jars ratio
- Replies: 6
- Views: 1202
Let total number of possible ways of selecting any 2 marbles be 'S'. probability of selecting 2 red marbles=8C2/S=28/S. ......(i) probability of selecting 1 red and 1 white marble=8C1*YC1/S. ...... (ii) Now if Y>=4 then YC1=4C1=4 which will render (ii) greater than (i). Statement (1): Y<=8 . No suff...
- by beatthegmat.garry
Mon Aug 15, 2011 9:54 pm- Forum: Data Sufficiency
- Topic: Jars ratio
- Replies: 6
- Views: 1202
We know that sqrt(a)*sqrt(b)=sqrt(ab). sqrt(9+sqrt(80)) sqrt(9-sqrt(80)=sqrt(9+sqrt(80)*(9-sqrt(80)) =sqrt(9^2-sqrt(80^2)) .................(a+b)(a-b)=a^2-b^2 =sqrt(81-80) =sqrt(1) =1 Hope this help :)
- by beatthegmat.garry
Sun Aug 07, 2011 5:58 pm- Forum: Problem Solving
- Topic: sqrt(9+sqrt(80)) sqrt(9-sqrt(80))=
- Replies: 3
- Views: 2442
Lets assume n1 be the no. of 8m ribbons. Lets assume n2 be the no. of 13m ribbons. Since total length=100, we can write: 8*n1 +13*n2=100 .........(1) Lets guess values of n1 and n2 such that eqn.(1) will be satisfied You will only find just one combination which is n1=6, n2=4. So I believe there are...
- by beatthegmat.garry
Wed Aug 03, 2011 7:51 am- Forum: Problem Solving
- Topic: ribbons in bag
- Replies: 4
- Views: 1267
In all you have 12 different combinations of head/tale and the numbers on the dice. You will have 6 ways to get a Tale and any number(from 1 to 6) on the dice. You will have 2 ways to get number 3 on the dice and any side (head or tale) of the coin. Please note that among the 8(6+2) favourable ways ...
- by beatthegmat.garry
Sat Jul 30, 2011 6:49 pm- Forum: Problem Solving
- Topic: Probability Man Guide
- Replies: 4
- Views: 1936
The quotient is not clear. Please use paranthesis where ever necessary
I see two kinds: (a) 5*(N^3)/8 (b) 5*N^(3/8)
- by beatthegmat.garry
Sat Jul 30, 2011 1:51 pm- Forum: Problem Solving
- Topic: probability again
- Replies: 15
- Views: 2936
If a number is divisible by 3^16 then the number should be able a multiple of 3^16. 63^n can be written as = (9*7)^n=(3^2 * 7)^n if you have noticed above each power of 63 will contribute 2 powers of 3 (i.e. 3^2). And for 63^n to be a multiple of 3^16 it has to contribute in atleast 16 powers of 3 (...
- by beatthegmat.garry
Thu Jul 28, 2011 7:44 pm- Forum: Data Sufficiency
- Topic: value of n?value of n?
- Replies: 12
- Views: 2032
Among any 3 consecutive integers you will find either 2 numbers one of them a multiple of 2 and the other a multiple of 3 or one number which is multiple of 6. Hence when you multiple 3 consecutive numbers the product will be a multiple of 6. From the above list 116 is the only number which is not a...
- by beatthegmat.garry
Wed Jul 27, 2011 6:57 am- Forum: Problem Solving
- Topic: 3 consecutives
- Replies: 5
- Views: 1195
x+y=3(x-y) ....given
(x+y)^2=3(x^2-y^2) .....multiplyin both sides by (x+y)
x^2 + y^2 +2xy=3x^2-3y2;
2xy=2x^2-2y^2;
xy/x^2-y^2=1
3xy/2(x^2-y^2)=3/2
Hence answer is 3/2 which is number 4.
- by beatthegmat.garry
Sun Jul 17, 2011 8:44 pm- Forum: Problem Solving
- Topic: Solve..
- Replies: 5
- Views: 1235
IMO the answer is E. Given: Also CD=8; AB=18 Statment1: C is in between A and B and hence CA=CB=9. Since CD=8 hence D is also in between A and B but we have no information whether its between A and C or B and C. So BD may be 1 or 17. Statement2: Since we dont get any information about the placement ...
- by beatthegmat.garry
Sun Jul 17, 2011 8:13 pm- Forum: Data Sufficiency
- Topic: Number Line
- Replies: 3
- Views: 1206