If x and y are non-zero integers, and 9x^4 – 4y^4 = 3x^2 + 2y^2, which of the following could be the value of x2 in terms of y?


A: (2y2+1)/3



I understand the diff of 2 sq's so
9x^4 – 4y^4 =

(3x^2+2y^2) (3x^2-2y^2)= (3x^2-2y^2)

then what?


Thanks