x and y only

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Source: — Data Sufficiency |

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by ssmiles08 » Sat Jun 20, 2009 5:05 am
1) x^2 = y^2

lets check values for case 1. (0,0) (3,-3)

0^2 = 0^2; x = y TRUE

(-3)^2 = (3)^2 x =/=y FALSE.

INSUFFICIENT.

2) |x|^2 + |y|^2 = 2|xy|

values to check case 2.

(0,0)
|0|^2 + |0|^2 = 2|0|; x = y TRUE


(3,-3)
|3|^2 + |-3|^2 = 2|-9|
9 + 9 = 18
x =/=y FALSE.

INSUFFICIENT.

As you can see together, it doesn't restrict anything. we can still use (0,0) and (3,-3) which gives us contradicting values.

Therefore it is (E)

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by ketkoag » Tue Jun 23, 2009 12:36 pm
thanks to confirm..