swerve wrote:A committee of 6 is chosen from 8 men and 5 women so as to contain at least 2 men and 3 women. How many different committees could be formed?
A. 635
B. 700
C. 1404
D. 2620
E. 3510
Since the committee must have 6 people, there are two cases that meet the given restrictions:
1) The committee has 2 men and 4 women
2) The committee has 3 men and 3 women
1) The committee has 2 men and 4 women
Since the order in which we select the men and women does not matter, we can use COMBINATIONS
We can select 2 men from 8 men in 8C2 ways (=
28 ways)
We can select 4 women from 5 women in 5C4 ways (=
5 ways)
So, the total number of ways to select 2 men and 4 women =
28 x
5 =
140
2) The committee has 3 men and 3 women
We can select 3 men from 8 men in 8C3 ways (=
56 ways)
We can select 3 women from 5 women in 5C3 ways (=
10 ways)
So, the total number of ways to select 2 men and 4 women =
56 x
10 =
560
So, the TOTAL number of ways to create the 6-person committee =
140 +
560 =
700
Answer: B
Cheers,
Brent