Q'1 on GMAT PowerPrep Practice Test

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jcan-gmatter: Junior | Next Rank: 30 Posts; Posts: 17; Joined: Thu Jul 05, 2007 9:08 am; Location: Kingston, Jamaica

Q'1 on GMAT PowerPrep Practice Test

by jcan-gmatter » Thu Sep 27, 2007 7:54 am

Hello all,

Tried searching the forum to see if this particular question was already posted. Didn't locate anything, so here goes ...

Question #1 on the GMAT Powerprep Practice Test

If (1/5)^m * (1/4)^18 = 1/2(10)^35, then m = ?

Can anyone assist with the above problem? I also posted a screenshot of the problem in question.

Thanks.

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: Question #1 on the GMAT Powerprep Practice Test

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Source: Beat The GMAT — Problem Solving | Thu Sep 27, 2007 7:54 am

kajcha: Master | Next Rank: 500 Posts; Posts: 321; Joined: Tue Aug 28, 2007 5:42 am; Thanked: 1 times

by kajcha » Thu Sep 27, 2007 8:08 am

2(10)^35 = 2(5*2)^35 = (4^18)*(5^35)

So, m = 35

Quote

samirpandeyit62: Master | Next Rank: 500 Posts; Posts: 460; Joined: Sun Mar 25, 2007 7:42 am; Thanked: 27 times

by samirpandeyit62 » Thu Sep 27, 2007 8:10 am

(1/5)^m * (1/4)^18 = 1/2(10)^35, then m = ?

=(1/5)^m * (1/2^2)^18 = 1/2(10)^35

=(1/5)^m * (1/2)^36 = 1/2(10)^35

(1/5)^m * (1/2)^35 *1/2 = 1/2(10)^35

now to bring 10 in the deniminator we need to multiply 5*2 no since 2 is raised to the power 35, so m=35 for this to be possible
so m=35

i.e. (1/5)^35 * (1/2)^35 *1/2
=1/(5*2)^35 *1/2

=1/2(10)^35

ans shoulld be D

Regards
Samir