Was 8 one of the option. Not sure if this is correct approach.
y = 8x+a cuts x axis at (-a/8,0) and cuts y axis at (0,a)
now question says area < 1
(a/8)*(a)/2 < 1
a^2 < 16
-4<a<4
range of a 4 -(-4) = 8
y = 8x+a cuts x axis at (-a/8,0) and cuts y axis at (0,a)
now question says area < 1
(a/8)*(a)/2 < 1
a^2 < 16
-4<a<4
range of a 4 -(-4) = 8












