BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Sphere and Cylonder problem

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Senior | Next Rank: 100 Posts
Posts: 51
Joined: Sat Oct 16, 2010 9:31 pm

Sphere and Cylonder problem

by AndyB » Sun Oct 09, 2011 3:35 am
Hello Everyone,

Anybody!!! Please help me in solving the below problem.

Q) A sphere with a diameter of 6cm is dropped in a circular cylindrical vessel that is partially filled with water.The diameter of the cylindrical vessel is 12 cm.If the

sphere is completely submerged in water how much will the level of water rise in lthe cylindirical vessel.

a)1 cm
b)2 cm
c)3 cm
d)4 cm
Top
Source: — Problem Solving |

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 3835
Joined: Fri Apr 02, 2010 10:00 pm
Location: Milpitas, CA
Thanked: 1854 times
Followed by:523 members
GMAT Score:770

by Anurag@Gurome » Sun Oct 09, 2011 3:47 am
AndyB wrote:A sphere with a diameter of 6cm is dropped in a circular cylindrical vessel that is partially filled with water.The diameter of the cylindrical vessel is 12 cm.If the sphere is completely submerged in water how much will the level of water rise in lthe cylindirical vessel.
Volume of the sphere = (4/3)*pi*(6/2)^3 = 36*pi cc

Say, the level of the water in the sphere rises by h cm.
Hence, the sphere replaces pi*[(12/2)^2]*h = 36*pi*h cc of water.

Therefore, 36*pi = 36*pi*h ---> h = 1

The correct answer is A.
Anurag Mairal, Ph.D., MBA
GMAT Expert, Admissions and Career Guidance
Gurome, Inc.
1-800-566-4043 (USA)

Join Our Facebook Groups
GMAT with Gurome
https://www.facebook.com/groups/272466352793633/
Admissions with Gurome
https://www.facebook.com/groups/461459690536574/
Career Advising with Gurome
https://www.facebook.com/groups/360435787349781/
Top
Master | Next Rank: 500 Posts
Posts: 197
Joined: Thu Sep 15, 2011 10:22 am
Thanked: 6 times
Followed by:2 members

by parul9 » Sun Oct 09, 2011 5:31 am
The water in cylinder will be displaced to accommodate the volume of the sphere.
So, volume of sphere = volume of displaced water in cylinder.

4/3*pi*3^3 = pi*6^2*h, where h is the height by which the water level will rise.

this gives us h = 1 cm.

So, A
Top
Post new topic Post Reply
• Page 1 of 1