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by ruplun » Fri Apr 29, 2011 9:43 pm
Of the 2500 voters participating in a local election , three times as many voted for candidate A as for Candidate B , and twice as many people voted for Candidate A as for Candidate C.If each voter choose either Candidate a,b or c or abstained, and 300 voters abstained , how many people voted for candidate C?

Please solve
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by parkman » Fri Apr 29, 2011 10:00 pm
Let 3x = A
x = B
3x/2 = C

2500 - 300 = 2200

3x + x + 3x/2 = 2200

4x + 3x/2 = 2200

Multiply both sides by 2

8x + 3x = 4400
11x = 4400
x=4400/11=400

C = 3(400)/2 = 1200/2 = 600
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by GMATGuruNY » Sat Apr 30, 2011 2:36 am
ruplun wrote:Of the 2500 voters participating in a local election , three times as many voted for candidate A as for Candidate B , and twice as many people voted for Candidate A as for Candidate C.If each voter choose either Candidate a,b or c or abstained, and 300 voters abstained , how many people voted for candidate C?

Please solve
Since 300 people abstained, the number who voted was 2500-300 = 2200.

We could plug in the answers, which would represent the number who voted for C.

Answer choice: C = 600.
Since twice as many voted for A, A = 1200.
Since 3 times as many voted for A as for B, B = 1200/3 = 400.
A + B + C = 1200 + 400 + 600 = 2200. Success!

The correct answer is 600.
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