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SQRT[(x-5)^2] = Abs (x-5)

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SQRT[(x-5)^2] = Abs (x-5)

by LSB » Mon Sep 01, 2008 3:46 am
Hi there - Writing the test tomorrow and would like to confirm one thing with you guys. Is it true that the below always holds. If this is true we never assume a negative sqrt ... correct?

SQRT[(x-5)^2] = Abs (x-5)

Thanks everyone
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by kshankker » Mon Sep 01, 2008 6:12 am
Yeah you are correct......squareroot (any term ) = positive ans.:
only (any term ) square = +/- ans.
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