swerve wrote:Audrey 4 hours to complete a certain job. Ferris can do the same job in 3hours. Audrey and Ferris decided to collaborate on the job, working at their respective rates. While Audrey worked continuously, Ferris took 3 breaks of equal length. If the two completed the job together in 2 hours, how many minutes long was each of Ferris' breaks ?
A. 5
B. 10
C. 15
D. 20
E. 25
Let the job = the LCM of the 3 times = 12 units.
Since Audrey's time alone = 4 hours, Audrey's rate = w/t = 12/4 = 3 units per hour.
Since Ferris's time alone = 3 hours, Ferris's rate = w/t = 12/3 = 4 units per hour.
Since Audrey works for the entire 2 hours, the work produced by Audrey = rt = 3*2 = 6 units.
Remaining work = (total job) - (Audrey's work) = 12 - 6 = 6 units.
Since Ferris's rate = 4 units per hour, the time for Ferris to produce the remaining 6 units = w/r = 6/4 = 1.5 hours.
Since Ferris works for 1.5 of the total 2 hours -- implying that his 3 breaks sum to 30 minutes -- the time for each break = 10 minutes.
The correct answer is
B.
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