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The Bryant's flower shop situated at the New Plaza complex s

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by hazelnut01 » Fri Apr 28, 2017 6:42 am
The Bryant's flower shop situated at the New Plaza complex stocks four types of flowers. There are 1/3 as many violets as carnations, and 1/2 as many tulips as violets. If there are equal no. of roses and tulips, what percent of the flowers in the shop are carnations?

(A) 6.25
(B) 20
(C) 33
(D) 50
(E) 60

OA=E
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by GMATGuruNY » Fri Apr 28, 2017 6:47 am
ziyuenlau wrote:The Bryant's flower shop situated at the New Plaza complex stocks four types of flowers. There are 1/3 as many violets as carnations, and 1/2 as many tulips as violets. If there are equal no. of roses and tulips, what percent of the flowers in the shop are carnations?

(A) 6.25
(B) 20
(C) 33
(D) 50
(E) 60
Let the number of carnations = the LCM of the denominators in the prompt = 3*2 = 6.
Since there are 1/3 as many violets as carnations, the number of violets = (1/3)(6) = 2.
Since there are 1/2 as many tulips as violets, the number of tulips = (1/2)(2) = 1.
Since there are an equal number of roses and tulips, the number of roses = 1.
Result:
carnations/total = 6/(6+2+1+1) = 6/10 = 60%.

The correct answer is E.
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by DavidG@VeritasPrep » Fri Apr 28, 2017 10:31 am
ziyuenlau wrote:The Bryant's flower shop situated at the New Plaza complex stocks four types of flowers. There are 1/3 as many violets as carnations, and 1/2 as many tulips as violets. If there are equal no. of roses and tulips, what percent of the flowers in the shop are carnations?

(A) 6.25
(B) 20
(C) 33
(D) 50
(E) 60

OA=E
And there's always good old-fashioned algebra. Call the number of carnations: x

Carnations = x
Violets = (1/3)x
Tulips = (1/2) * (1/3)x = (1/6)x
Roses = Tulips = (1/6)x
Total = x + (1/3)X + (1/6)x + (1/6)x = (10/6)x = (5/3)x

Carnations/Total = x/[(5/3)x] = 3/5 = 60%. The answer is E
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by DavidG@VeritasPrep » Fri Apr 28, 2017 10:33 am
A little time-saver: the moment you realize that carnations constitute more than half of the total (carnations = x and everything else = (1/3)x + (1/6)x + (1/6)x = (4/6)x, you know that the carnations constitute more than 50% of the total, so you're done, the answer has to be E
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Re: The Bryant's flower shop situated at the New Plaza complex s

by Scott@TargetTestPrep » Mon Apr 13, 2020 3:53 am
hazelnut01 wrote: ↑
Fri Apr 28, 2017 6:42 am
 The Bryant's flower shop situated at the New Plaza complex stocks four types of flowers. There are 1/3 as many violets as carnations, and 1/2 as many tulips as violets. If there are equal no. of roses and tulips, what percent of the flowers in the shop are carnations?

(A) 6.25
(B) 20
(C) 33
(D) 50
(E) 60

OA=E
We can let the number of carnations be 60, so 20 are violets and 10 are tulips and 10 are roses. So the percent of the flowers that are carnations is 60 / (60 + 20 + 10 + 10) = 60/100 = 60%.

Answer: E

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