Ashetty wrote:The diameter of circle S is equal in length to a certain square. The diameter od circle T is equal in length to a diagnol of the same square. The area of circle T is how many times the area of circle S?
Ans is 2.
let square side = s
diagonal of square = √2 s
or
√s^2+s^2 = √2 s
area of circle S = TT (s/2)^2 = TT s^2/4
area of circle T = TT (√2 s/2)^2 = TT 2s^2/4 = TT s^2/2
T:S
TT s^2/2 : TT s^2/4 (x4, remove TT and s^2)
2 : 1












