vmt not equal 0. Therefore none of them is zero.
from 1:
m>v^2
therefore m >0
therefore v^2*m^3*t^4>0 (only m could make this negative, squares and forth powers are always positive)
Sufficient
from 2:
m>t^4
again m>0
therefore v^2*m^3*t^4>0
Sufficient
IMO answer D
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ballubalraj
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seer bhai!iamseer wrote:vmt not equal 0. Therefore none of them is zero.
from 1:
m>v^2
therefore m >0
therefore v^2*m^3*t^4>0 (only m could make this negative, squares and forth powers are always positive)
Sufficient
from 2:
m>t^4
again m>0
therefore v^2*m^3*t^4>0
Sufficient
IMO answer D
In my screen shot its showing
m> t ^(-4)
> 1/(t^4)
m>0
even if t is a imaginary number, m>0
SO pick D
yes, you are right. Thanks for pointing that gmatmachoman.gmatmachoman wrote: seer bhai!
In my screen shot its showing
m> t ^(-4)
> 1/(t^4)
m>0
even if t is a imaginary number, m>0
SO pick D
the explanation holds as long as t has an even power.
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