BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

GMAT Prep Q

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Senior | Next Rank: 100 Posts
Posts: 30
Joined: Sat May 21, 2011 7:28 am
by KItuz » Sun Jun 19, 2011 5:41 pm
Three boxes of supplies have an average weight of 7 kg and a median weight of 9 kg. What is the maximum possible weight, in kg of the lightest box?
1
2
3
4
5

Ans given = 3

My ans = 1 Please help me understand where I am wrong.
Sum of 3 weights = 21
Median = 9 => sum of 1st and 3rd = 12
Given 1st <= 9 and Last >= 9
Max of Last = 11 => Least of First = 1 ?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
User avatar
Legendary Member
Posts: 965
Joined: Thu Jan 28, 2010 12:52 amFollowed by: 34 members
Thanked: 156 times
GMAT Score:720

by vineeshp » Sun Jun 19, 2011 6:32 pm
Your mistake is that you taken the max value for the heaviest box.

We have to find the maximum possible weight of the smallest box.
In this case, 3, 9, 9 is a valid combination of values. Do you agree?
Another possible combination is 2,9,10. So 1 can never be the maximum possible value of the lightest box as we have already identified 2 combinations in which weight of the lightest box can be 2 or 3.
Vineesh,
Just telling you what I know and think. I am not the expert. :)
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Senior | Next Rank: 100 Posts
Posts: 56
Joined: Mon Feb 07, 2011 7:57 am
Thanked: 1 times
GMAT Score:600

by crisro » Wed Jun 22, 2011 7:36 am
(a+b+c)/3=7, b=9,a<=b<=c

a+c=12, we only have three options

1+11
2+10
3+9

the maximum weight of the lightest is the highest value between the small values on the left
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1