DCS80 wrote:[(8^2)(3^3)(2^4)]/(96^2)
i understand the concept of breaking down 96^2 in terms of the numerator, but how do you factor it appropriately? maybe I'm missing a simple concept, but the answer is vague in the explanations section.
thx
when it comes to breaking down powers of integers -- if you don't immediately see any tricks or shortcuts, just break all the integers down into
primes. (in fact, this should almost be a knee-jerk reaction -- if you see powers of specific whole numbers, your brain should yell, "primes!")
so, here, that would include not only breaking down the 96 in the denominator, but also breaking the 8 (in the numerator) down into more 2's.
Ron has been teaching various standardized tests for 20 years.
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