(T1 + T2 + T3)/3 = 40R.k91 wrote:The average temperature for 1st, 2nd, and 3rd june was 40^0C. the average for 2nd, 3rd and 4th was 41^0C, that for the 4th 42^oC. What was the temperature on 1st june???
T1 + T2 + T3 = 120 -- (1)
(T2 + T3 + T4)/3 = 41
T2 + T3 + T4 = 123 -- (2)
Subtracting (1) from (2),
T4 - T1 = 3
If T4 = 42,
42 - T1 = 3
T1 = 39
The temperature was 39 C on 1st of June.
What is the source of this problem?
