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by massi2884 » Sat May 26, 2012 5:09 am
m+n=y+e+z+4
=(-5-4)+(n-y)+(10-e)+4
=5+e+y-y-e=5
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by Anurag@Gurome » Sat May 26, 2012 5:34 am
m = (z + 4) and n = (y + e)

Hence, (m + n) = (z + y + e + 4)

Now, (z + e) = 10
And, (y + 4) = -5 --> y = -9

Hence, (m + n) = (10 - 9 + 4) = 5

The correct answer is C.
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by GmatKiss » Sat May 26, 2012 10:31 am
IMO: C, even i got a problem like this in cat.

Nice refresher, thanks :)
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by vickythakre » Sat May 26, 2012 2:06 pm
Anurag@Gurome wrote:m = (z + 4) and n = (y + e)

Hence, (m + n) = (z + y + e + 4)

Now, (z + e) = 10
And, (y + 4) = -5 --> y = -9

Hence, (m + n) = (10 - 9 + 4) = 5

The correct answer is C.
Hi Anurag,

Can you please from starting that how to decipher these kinds of table.
I am missing even the basics here.

Best,

BT
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