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geometry

by Lattefah84 » Mon Feb 01, 2010 4:25 am
The length of a rectangular garden surrounded by a walkway is twice its width. If difference between the length and width of just the rectangular garden is 10 meters, what will be the width of the walkway if just the garden has width 6 meters?

(it is not typical question with an official answer, but i stuck here :( )

Can someone explain how is it done?


Thanks!
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by ajith » Mon Feb 01, 2010 4:38 am
Lattefah84 wrote:The length of a rectangular garden surrounded by a walkway is twice its width. If difference between the length and width of just the rectangular garden is 10 meters, what will be the width of the walkway if just the garden has width 6 meters?

(it is not typical question with an official answer, but i stuck here :( )

Can someone explain how is it done?


Thanks!
say a is the length and b is the width

a =2b
a-b = 10

b =10
a=20

now b -2w =6
2w =4
w=2

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by sanju09 » Mon Feb 01, 2010 5:26 am
Lattefah84 wrote:The length of a rectangular garden surrounded by a walkway is twice its width. If difference between the length and width of just the rectangular garden is 10 meters, what will be the width of the walkway if just the garden has width 6 meters?

(it is not typical question with an official answer, but i stuck here :( )

Can someone explain how is it done?


Thanks!
If garden is 6 meter broad, then its length is 16 meter. If the walkway has a uniform width of d meter, then

16 + 2 d = 2 (6 + 2 d) or d = [spoiler]2[/spoiler] meter.
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by bluefaith » Thu Mar 24, 2016 7:51 pm
This is my answer for this question. Quite easy but you need to draw a picture to image.
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