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thailandvc
- Senior | Next Rank: 100 Posts
- Posts: 49
- Joined: Fri Jul 24, 2009 5:18 am
(X+1)^3 <= 64, What is the range?
Ans: Cuberoot [(x+1)^3] <= cuberoot (64) => Absolute value (X+1) <= 4
My question, I thought you can't divide by variables in equalities. Since you dont know if x+1 is positive or negative. If it is a square i understand but...
Ans: Cuberoot [(x+1)^3] <= cuberoot (64) => Absolute value (X+1) <= 4
My question, I thought you can't divide by variables in equalities. Since you dont know if x+1 is positive or negative. If it is a square i understand but...

















