inequality problem

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inequality problem

by thailandvc » Sun Aug 09, 2009 10:15 pm
(X+1)^3 <= 64, What is the range?
Ans: Cuberoot [(x+1)^3] <= cuberoot (64) => Absolute value (X+1) <= 4

My question, I thought you can't divide by variables in equalities. Since you dont know if x+1 is positive or negative. If it is a square i understand but...
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by tohellandback » Sun Aug 09, 2009 10:19 pm
i am assuming we are to find the range of X.
I think we can't find it
max value will be 3.
there is no least value because for any negative value the cube will be <64
The powers of two are bloody impolite!!