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|xy| > x^2y^2 ?

Expert replies
Source: — Data Sufficiency |

by [email protected] » Sun Oct 13, 2013 3:32 pm
Hi guerrero,

This DS question is perfect for TESTing values, especially since we are told NOTHING about X and Y to begin....

We're asked if |XY| > (X^2)(Y^2)? This is a Yes/No question.

Fact 1: 0 < X^2 < 1/4

This tells us that -1/2 < X < 1/2
If X = 0, then it doesn't matter what Y is, and the answer to the question is NO
If X = .1 and Y = 1, then the answer to the question is YES
Fact 1 is INSUFFICIENT

Fact 2: 0 < Y^2 < 1/9

This tells us that -1/3 < Y < 1/3
We can use the exact same "pattern" from Fact 1 here in Fact 2 (we'll just flip-flop the X and Y values)
If Y = 0, then it doesn't matter what the X is, and the answer to the question is NO
If Y = .1 and X = 1, then the answer to the question is YES
Fact 2 is INSUFFICIENT

Combined we know:
-1/2 < X < 1/2
-1/3 < Y < 1/3

Number Property knowledge comes in handy here.
|XY| will be a positive fraction.
(X^2)(Y^2) will be a SMALLER positive fraction because we're squaring two fractions and multiplying them.

The answer to the question is ALWAYS YES.
Together SUFFICIENT

Final Answer: C

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
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by lunarpower » Mon Oct 14, 2013 2:48 am
A student called my attention to this thread.
[email protected] wrote:Fact 1: 0 < X^2 < 1/4
If
This tells us that -1/2 < X < 1/2
If X = 0, then it doesn't matter what Y is, and the answer to the question is NO
If X = .1 and Y = 1, then the answer to the question is YES
Fact 1 is INSUFFICIENT

Fact 2: 0 < Y^2 < 1/9

This tells us that -1/3 < Y < 1/3
We can use the exact same "pattern" from Fact 1 here in Fact 2 (we'll just flip-flop the X and Y values)
If Y = 0, then it doesn't matter what the X is, and the answer to the question is NO
If Y = .1 and X = 1, then the answer to the question is YES
Fact 2 is INSUFFICIENT
Rich -- I agree that testing cases is the best way to go here, but, careful with the due diligence. We know that 0 < x^2 < 1/4. So x = 0 is not an allowed value; the allowed values are everything between -1/2 and +1/2, except 0.
For y it's pretty much the same deal, with 1/3 substituted for 1/2.
Ron has been teaching various standardized tests for 20 years.

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by lunarpower » Mon Oct 14, 2013 2:49 am
So, when you test cases, it has to be a little more interesting. Basically, in statement 1 you have to pick a value of y that's greater than 1/|x| (or less than -1/|x|), and vice versa for statement 2.
E.g., in statement 1, if x = 1/3, then you have to pick y > 3 or < -3.
(If you don't see why, try it! You'll notice what happens if x = 1/3 and y = 3. From there, you can discern pretty quickly why y has to be bigger.)

Also, with the two statements together, if you don't IMMEDIATELY see the number properties at work, just start testing values.
Once you try a couple of values that fit both statements together, it will become abundantly clear what is going on, even if you didn't think about "fraction properties" to begin with.
Ron has been teaching various standardized tests for 20 years.

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Pueden hacerle preguntas a Ron en castellano
Potete chiedere domande a Ron in italiano
On peut poser des questions à Ron en français
Voit esittää kysymyksiä Ron:lle myös suomeksi

--

Quand on se sent bien dans un vêtement, tout peut arriver. Un bon vêtement, c'est un passeport pour le bonheur.

Yves Saint-Laurent

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by mevicks » Mon Oct 14, 2013 7:46 am
guerrero wrote:|xy| > x^2y^2 ?

(1) 0 < x^2 < 1/4

(2) 0 < y^2 < 1/9
Q: Is |xy| > x²y² ?
Square both sides:

Is x²y² > (x²y²)²
?

St1: Gives no information about y, INSUFFICIENT
St2: Gives no information about x, INSUFFICIENT

St1+St2:

Let x² = y² = (1/10)
(1/10) is less than both (1/4) and (1/9) & greater than 0

So the target question becomes Is (1/100) > (1/100)² ?
The answer is YES, and we can test other values to prove that this is always true for fractions(Basically a square of a fraction is smaller than the fraction itself)

Answer C

Regards,
Vivek
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