Well 29! sounds right to me .. 30 would definitely add a additional 0

when u take 25! itself there will be 6 zeros at the end.....this can be calculated in a diff way...

number of 5s in 25 = 5
number of 25s in 25 = 1
so total number of zeros = 6...

jangojess wrote:when u take 25! itself there will be 6 zeros at the end.....this can be calculated in a diff way...

number of 5s in 25 = 5
number of 25s in 25 = 1
so total number of zeros = 6...

Sorry, Didnt get ya...
Can you explain this further . Also what is your final answer?

jangojess wrote:when u take 25! itself there will be 6 zeros at the end.....this can be calculated in a diff way...

number of 5s in 25 = 5
number of 25s in 25 = 1
so total number of zeros = 6...

I agree with you jangojess... 25! would as such suffice as an answer, but from the choices isnt 29! the appropriate

Read the question properly, it asks for the maximum value of "n" , 25 is not the maximum value "n" can take but 29 is ...

Regards

Can someone explain this one in some detail?

dingo001 wrote:Can someone explain this one in some detail?

So is the OA wrong. It has to be 29!

Yup.. the OA is wrong .. the answer should be 29! ...

Agree with Gabriel the ans should be 29!

coz 29 has 6 pairs of 5,2 which would lead to 6 trailing zero's.

could some one pls explain this one to me again.

29! = 8.84176199 × 10^30 ... as per google calculator

which is also 884176199 × 10^22,

this numbser does not satisfy the question asked.

Could you pls help me clarify my basic understanding of a question such as this?

Thanks so much

i think 30 will have 6 pairs of 5,2 and not 29.....

Suyog wrote:i think 30 will have 6 pairs of 5,2 and not 29.....

No 30 has 7 fives and will have surely have 7 twos... so total zeroes is 7 not six..it cant be 30... please comment

i think i'm missing something....how 7?

here is a copy of the reply I got from Samir Pandey -

if u try the same on the windows calculator in scientific mode u will get the answer.

the approach here is very simple, 29! will be a nos

now the nos of 0's in 29! will depend upon the nos of pairs of 5,2 in 29! i.e 5*2 =10 which produces a 0

so to count the nos of pairs of 5,2 in 29! we just need to count the nos of 5 's (this is universal) coz nos of 5's will be more than 2's

the best way to count it is bu divinding 29 or any n by 5 & taking the qoutient, 5^2 & taking the quotinet only .....so on with higher powers of 5 till we get a non zero quotient

using this appraoach we can say

29/5 = 5 (quotient)

29/25 = 1

other powers will give 0 qoutient

so nos of 5's in 29! is 5+1 hence 0's =6

for 30! we have

30/5 =6
30/25 =1

so 7 zeroes

Thanks again Samir