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by mandeepak » Tue Oct 30, 2007 12:08 pm
Last Sunday a certain store sold copies of Newspaper A for $1.00 each and copies of Newspaper B for $1.25 each, and the store sold no other newspapers that day. If r percent of the store’s revenues from newspaper sales was from Newspaper A and if p percent of the newspapers that the store sold were copies of newspaper A, which of the following expresses r in terms of p?

A. 100p / (125 – p)
B. 150p / (250 – p)
C. 300p / (375 – p)
D. 400p / (500 – p)
E. 500p / (625 – p)
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by Suyog » Tue Oct 30, 2007 2:27 pm
Solved earlier by someone....

Revenue = Price x Quantity

Since we’re talking percent, I’ll assume that the quantity of all newspapers sold is 100.

From that, if the quantity of newspapers A sold is p, the quantity of newspapers B sold must be 100-p.

The revenue from newspapers A is ($1.00)p and the revenue from newspapers B is ($1.25)(100-p) which equals to 125 – 1.25p

Since r is the percentage of revenue A from the over all revenue,

r = [ (revenue A) / (revenue A + revenue B) ] x 100

So r = [p / (p + (125 – 1.25p)] x 100 = 100p / (125 – 0.25p)

Since the coefficient of p is 0.25, I multiplied the numerator and denominator by 4, so the result is:

400p / (500 – p)
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