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This is an easy question....help

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Re: This is an easy question....help

by iamcste » Wed Nov 19, 2008 2:34 pm
GMATCRUSHER wrote:could a few of you please evaluate this question?

2^[(4-1)^2] / 2^(3-2)

2^(3^2) divided 2 ^1

2^9 div 2^1

2^ 8 ( a^m/a^n=a^m-n)
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by GMATCRUSHER » Wed Nov 19, 2008 3:44 pm
Thank you so much, I see my error, I multiplied 3x2 rather than take 3^2.......
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