BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATBootcamp Starts Sep 21
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE BOOTCAMP

Live Online Bootcamp Class with Top GMAT Expert Chris Peckover

Sep 21 to Oct 9, 2026

Schedule
Mon to Fri · 7:00 to 10:00 PM ET
Included
Live classes + 6 months of TTP OnDemand
  • Boost your GMAT score in less than one month in a live online class
  • 6 months access to TTP OnDemand video courses included
View bootcamp & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

The results of a certain experiment included 6 data values

Expert replies
by Robinmrtha » Wed Jun 17, 2009 3:02 am
The results of a certain experiment included 6 data values that were all multiples of the same number c, namely, c, 8c, 2c, 5c, 4c, and 4c. Was the average (arithmetic mean) of the 6 data values greater than 8?
(1) c < 4
(2) c > 2
Join the discussion
Source: — Data Sufficiency |

by shashank.mehra » Wed Jun 17, 2009 5:08 am
AM = Sum of (c, 8c, 2c, 5c, 4c, and 4c) / 6 = 4c

1) C< 4 gives AM < 16 Not sufficient
2) C > 2 give AM > 8 Sufficient

B
Join the discussion

by abhinav85 » Wed Jun 17, 2009 11:51 am
Hey Shashank

AM = Sum of (c, 8c, 2c, 5c, 4c, and 4c) / 6 = 4c

1) C< 4 gives AM < 16 Not sufficient
2) C > 2 give AM > 8 Sufficient

B

I think the question is asking that what is the AM of values greater than
8??

IMO C
Join the discussion

by Domnu » Wed Jun 17, 2009 11:56 am
I think the answer is B. The average is 4c, and we need c > 2. c < 4 says that the average is less than 16, but this is meaningless to us.
Have you wondered how you could have found such a treasure? -T
Join the discussion

by ssmiles08 » Wed Jun 17, 2009 12:00 pm
IMO B as well.

average is 4c and if C > 2 (lets say 2.1) it will still be greater than 8.
Join the discussion