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Quadratic equations: Real solutions

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by selango » Wed Jul 07, 2010 6:06 pm
what is the source of this question?

Can you post the answer choices?
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by Rich@VeritasPrep » Wed Jul 07, 2010 6:58 pm
>>>
Last edited by Rich@VeritasPrep on Wed Jul 07, 2010 8:06 pm, edited 1 time in total.
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by vivekmalhotra » Wed Jul 07, 2010 7:43 pm
Hi Raz,

The equation |x|^2 - 5|x|+6=0

will rather breaks down to:

(|x| - 2)(|x| - 3) = 0

giving |x| = 2 or |x| = 3

so the equation should have 4 solutions: 2, -2, 3, -3

Am I missing something here??

Thanks!!
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by Rich@VeritasPrep » Wed Jul 07, 2010 8:06 pm
Nope! Just a misread on my part. You're absolutely correct!
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