BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

a ps from gmat club

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Problem Solving |
User avatar
Master | Next Rank: 500 Posts
Posts: 436
Joined: Tue Feb 08, 2011 3:07 am
Thanked: 72 times
Followed by:6 members

by manpsingh87 » Sat Apr 16, 2011 12:57 am
diebeatsthegmat wrote:If two numbers are selected from 1,2,3,4 and 5 with replacement, what is the probability that product of two numbers is less than 10 ?

A. 4/5
B. 9/16
C. 16/25
D. 9/25
E. 3/5
no. of ways of selecting first number without restriction =5, no. of ways of selecting selecting second number without restriction=5,

now product will be less than 10 if the numbers selected were following
(1,1),(1,2),(1,3),(1,4),(1,5),(2,1),(2,2),(2,3),(2,4)(3,1),(3,2),(3,3),(4,1),(4,2),(5,1)..!!!

hence required probability would be=15/25=3/5..!!! hence E
Last edited by manpsingh87 on Sat Apr 16, 2011 4:14 am, edited 1 time in total.
O Excellence... my search for you is on... you can be far.. but not beyond my reach!
Top
User avatar
Legendary Member
Posts: 582
Joined: Tue Mar 08, 2011 12:48 am
Thanked: 61 times
Followed by:6 members
GMAT Score:740

by force5 » Sat Apr 16, 2011 3:08 am
15/25 = 3/5 IMO-E
Top
Post new topic Post Reply
• Page 1 of 1