alanforde800Maximus wrote:The integers v, w, x, y and z are such that 0 < v < w < x < y < z. The average of these integers is 36 and median of these 5 integers is 28. What is the greatest possible value of Z?
a) 128
b) 130
c) 140
d) 132
e) 120
The average of these integers is 36
So, (v + w + x + y + z)/5 = 36
So,
v + w + x + y + z = 180
The median of these 5 integers is 28
Since x is the middlemost value (in ascending order), we know that x =
28
So, we have v, w,
28, y, z
If we want to MAXIMIZE the value of z, we must MINIMIZE the remaining values.
Since v is a positive integer, the smallest value of v is 1
1, w,
28, y, z
Since v < w, the smallest value of w is 2
1, 2,
28, y, z
Since x < y, the smallest value of y is 29
1, 2,
28, 29, z
Since
v + w + x + y + z = 180, we know that 1 + 2 +
28 + 29 + z = 180
Simplify: 60 + z = 180
z = 120
Answer:
E
RELATED VIDEO
- Mean, median and mode:
https://www.gmatprepnow.com/module/gmat ... /video/800
