Statement 1: Consider the the following two examples,srcc25anu wrote:If x and y are both integers, which is larger, x^x or y^y?
1.x = y + 1
2.x^y > x and x is positive.
- x = 2 and y = 1, x^x > y^y
x = -1 and y = -2, x^x < y^y
Statement 2: As x is a positive integer, x^y will be greater than x^x only if x > 1 and y > 1.
Consider the the following two examples,
- x = 2 and y = 3, x^x < y^y
x = 3 and y = 2, x^x > y^y
1 & 2 Together: Now, we know that both x and y are greater than 1 and x = y + 1
Hence, x^x = (y + 1)^(y + 1) > y^y
Sufficient
The correct answer is C.
