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RBBmba@2014
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HI Math Experts,
This is not exactly any question from any Test prep companies. Rather it's just a basic question to get some clarification on my doubts, so that I can have better understanding of the actual problem.
Here's the question -
In how many ways can a person post 5 letters in 4 letter boxes ?
And here goes my doubts -
Method 1: Say, there are 4 boxes - A,B,C & D that need to be filled by the 5 letters L1 to L5.
Now, L1 can be posted in either A, B, C, or D i.e. 4 ways. This holds good for other letters(L2/3/4/5) as well.
So the total no of ways in which 5 letters can be posted in 4 boxes will be 4 x 4 x 4 x 4 x 4 = 4^5=1024.
Now, another option coming to my mind -
Method 2: A can be filled in by either L1, L2, L3,L4, or L5 i.e. 5 ways. B in 4 ways, C in 3 ways and D in 2 ways (i.e. total 5 x 4 x 3 x 2=120 ways). Still one letter remaining which can be posted in any of the 4 boxes i.e 4 ways.
So the total no of ways in which 5 letters can be posted in 4 boxes or 4 boxes can be filled in by 5 letters, will be 120 x 4 =480.
Now, any of these two should be the proper method. Can you please explain which one is so and WHY ?
Would much appreciate your detail explanation.
Thank you!
This is not exactly any question from any Test prep companies. Rather it's just a basic question to get some clarification on my doubts, so that I can have better understanding of the actual problem.
Here's the question -
In how many ways can a person post 5 letters in 4 letter boxes ?
And here goes my doubts -
Method 1: Say, there are 4 boxes - A,B,C & D that need to be filled by the 5 letters L1 to L5.
Now, L1 can be posted in either A, B, C, or D i.e. 4 ways. This holds good for other letters(L2/3/4/5) as well.
So the total no of ways in which 5 letters can be posted in 4 boxes will be 4 x 4 x 4 x 4 x 4 = 4^5=1024.
Now, another option coming to my mind -
Method 2: A can be filled in by either L1, L2, L3,L4, or L5 i.e. 5 ways. B in 4 ways, C in 3 ways and D in 2 ways (i.e. total 5 x 4 x 3 x 2=120 ways). Still one letter remaining which can be posted in any of the 4 boxes i.e 4 ways.
So the total no of ways in which 5 letters can be posted in 4 boxes or 4 boxes can be filled in by 5 letters, will be 120 x 4 =480.
Now, any of these two should be the proper method. Can you please explain which one is so and WHY ?
Would much appreciate your detail explanation.
Thank you!













